@仗剑走天涯 “不管昨天三根线是什么状态,只要满足今天三线都红的,以后三线持续翻红的不入选,只选三线同时红的这一天.” 也就是说:昨天三根线有1根或2根或3根线是绿的,今天3根全部是红的。公式如下:
M1:=MA(C,5)>REF(MA(C,5),1) AND MA(C,10)>REF(MA(C,10),1) AND MA(C,20)>REF(MA(C,20),1);
M2:=MA(C,5)<REF(MA(C,5),1) OR MA(C,10)<REF(MA(C,10),1) OR MA(C,20)<REF(MA(C,20),1);
M1 AND REF(M2,1) AND NOT(DYNAINFO(9)=0);